Loading...

Pattern-2

Programme:

#include <stdio.h>
 
main() {
 
  int n, c, k, space, count = 1;
 
  printf("Enter number of rows : ");
  scanf("%d", &n);
 
  space = n;
 
  for (c = 1; c <= n; c++) {
 
    for (k = 1; k < space; k++)
      printf(" ");
 
    for (k = 1; k <= c; k++) {
      printf("*");
 
      if (c > 1 && count < c) {
 
        printf("A");
        count++;
 
      }
    }
 
    printf("\n");
    space--;
    count = 1;
 
  }
 
  return 0;
}

Output:

Enter number of rows : 6
     *
    *A*
   *A*A*
  *A*A*A*
 *A*A*A*A*
*A*A*A*A*A*